Quote:
Originally Posted by R.D. Silverman
Yes, I was looking for formula %9. I was hoping that it might be
symmetric. It is not, but I thought that if it isn't, it might have a
representation as a sextic not in (z+1/z), but rather [with Z = 2^53]
in (z + 2/z). It seems that it does, but the constant is much too large.
Perhaps we might try a sextic in (z + k/z) for some other value of k?

I am not familiar with the syntax of Maple.
The above calculation should solve for (c1, c2, c3, .....) where
(z + 2/z)^6 + c1 (z + 2/z)^5 + c2 (z + 2/z)^4 + c3 (z + 2/z)^3 + .... =
z^6 *(z^12 + 2z^11  22z^10  44z^9 ........ etc [expression %9])